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9y^2-y-5=0
We add all the numbers together, and all the variables
9y^2-1y-5=0
a = 9; b = -1; c = -5;
Δ = b2-4ac
Δ = -12-4·9·(-5)
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{181}}{2*9}=\frac{1-\sqrt{181}}{18} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{181}}{2*9}=\frac{1+\sqrt{181}}{18} $
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